PQRS is a trapezium in which PQ//RS. Diagonals PR and QS intersect at M, then
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PQRS is a trapezium in which PQ//RS. Diagonals PR and QS intersect at M, then the following can happen that is
PO /QO=RO/SO
if you prove this then
As PQ∣∣RS and PR and QS are transversal
∠OSR=∠OQP (alternate angles)
∠ORS=∠OPQ (alternate angles)
then ,△SOR∼△POQ
then SO/PO=RO/QO=SR/PQ
then,
QO/PO=RO/SO (PROVED)
sorry buddy but your question was not clear so I assumed that it may be your question....
if it helps then mark the brainiest and click thanks.
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