Question

PQRS is a trapezium, in which pQ || RS, PQ = 5.4 cm, RS = 7.1 cm and the distance between the
parallel lines is 3.6 cm. Find the area of the trapezium PQRS.​

Answer 1

Given :

• PQRS is a trapezium
• PQ || RS
• PQ = 5.4 cm
• RS = 7.1 cm
• Distance between them = 3.6 cm

To Find :

The area of PQRS.

Solution :

Here we have to use the formula of area of trapezium.

Required Formula :

Area of trapezium = ½ × (a + b) × d

where,

• a & b = The parallel sides
• d = Distance between them

Explanation :

We know that if we are given the measure of the parallel sides and the distance between them of a trapezium and is asked to find its area then our required formula is,

Area of trapezium = ½ × (a + b) × d

where,

• a = 5.4 cm
• b = 7.1 cm
• d = 3.6 cm

Using the required formula and substituting the values,

⇒Area of trapezium = ½ × (a + b) × d

⇒ Area of trapezium = ½ × (5.4 + 7.1) × 3.6

⇒ Area of trapezium = 1 × (5.4 + 7.1) × 1.8

⇒ Area of trapezium = 1 × 12.5 × 1.8

⇒ Area of trapezium = 1 × 22.5

⇒ Area of trapezium = 22.5

∴ Area of trapezium = 22.5 cm².

Area of the trapezium PQRS is 22.5 cm².

Explore More :

• Area of rectangle = Length × Breadth
• Area of square = Side × Side
• Area of parallelogram = Base × Height
• Area of triangle = ½ × Base × Height
• Perimeter of rectangle = 2(Length + Breadth)
• Perimeter of square = 4 × Side