Question

pqrs is a trapezium pQ parallel to RS PT perpendicular RS QT perpendicular RS PQ =8 PS=6 root 2​

Answer 1

Step-by-step explanation:

Solving as per the question in the image given:

Referring to the given figure, we have

PQRS is a trapezium

PQ // RS

E and F are points on PQ and RS which intersects diagonal SQ at G

Now, considering ΔGEQ and ΔGFS, we have

∠EGQ = ∠FGS ……. [vertically opposite angles]

∠EQG = ∠FSG …….. [alternate angles]

∠GEQ = ∠GFS …… [alternate angles]

∴ By AAA similarity, ΔGEQ ~ ΔGFS

Since the corresponding sides of two similar triangles are proportional to each other.

∴ \frac{EQ}{FS} = \frac{GQ}{GS}

FS

EQ

=

GS

GQ

⇒ EQ * GS = GQ * FS

Hence proved

sorry I don't know the answer perfectly but I think it will help you to solve your answer

sorry

and

thank u