Question

pqrs is a trapezium with PQ|| Aisa if angle P = 30 degree angle Q = 50 degree find angle A and angle s​

Answer 1

REF.Image

Since PQ||SR, and PS is transversal then

∠P+∠S=180

∘

(sum of consecutive interior angles on the same of transversal is 180

∘

)

30

∘

+∠S=180

∘

∠S=180

∘

−30

∘

∠S=150

∘

Since PQ||SR , and QR is transversal then

∠Q+∠R=180

∘

(sum of consecutive interior angles on the same side of transversal is 180

∘

)

50

∘

+∠R=180

∘

∠R=180

∘

−50

∘

∠R=130

∘

Answer 2

Step-by-step explanation:

angle a + s = 360- (30+50)

= 360-80

= 280

angle a = s so, 280/2

= 140°