Question

PQRS is a trapezium with PQ and RS parallel. If PQ = 6, QR = 5, RS = 3, PS = 4, ZP =90degrees​

Answer 1

Area of Trapezium PQRS =  18  Sq units

Step-by-step explanation:

PQ = 6, QR = 5, RS = 3, PS = 4, ∠P =90°

PQ ║ RS

as ∠P =90°

=> PS is perpendicular distance between  PQ  & RS

Area of Trapezium = (1/2)(PQ + RS)* PS

= (1/2) (6 + 3) * 4

=  2 * 9

= 18  Sq units

Area of Trapezium PQRS =  18  Sq units

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