PQRS is a trapezium with PQ || SR and <p=<q=50
a.Prove that PQ=SR
b.Is <S=<R
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Since PQ||SR, and PS is transversal then
∠P+∠S=180
∘
(sum of consecutive interior angles on the same of transversal is 180
∘
)
30
∘
+∠S=180
∘
∠S=180
∘
−30
∘
∠S=150
∘
Since PQ||SR , and QR is transversal then
∠Q+∠R=180
∘
(sum of consecutive interior angles on the same side of transversal is 180
∘
)
50
∘
+∠R=180
∘
∠R=180
∘
−50
∘
∠R=130
∘
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