PQRS is a trapezium with PQ||SR. Side SR is produced to X such that RX=PQ. Prove that ar(∆PQR)=ar(∆QRX)
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vaishakhgatty63:
we should prove ar of triangle psq = ar of triangle qrx
is said right
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it's totally wrong
in ques it is mentioned else
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in triangle pqr and triangle qrx
pq=rx given
angle pqr=angle qrx alternate angles
also pqrx is a parallelogram as pq=RX and pq parallel to RX
thus angle P=X
by ASA both are congruent
pq=rx given
angle pqr=angle qrx alternate angles
also pqrx is a parallelogram as pq=RX and pq parallel to RX
thus angle P=X
by ASA both are congruent
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