PQRS is an isoceles trapezium, l[PQ] = 7cm, seg PM is perpendicular to seg SR, l[SM) = 3 cm, Distance between two parallel side is 4cm, find the area of PQRS
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Length of PQ = 7 cm
Length of PM = distance between two parallel sides = 4 cm
Length of SM = 3cm
see figure, length of SR = SM + MN + NR
because PQRS is isosceles trapezium, so, SR = NR = 3cm and MN = PQ = 7cm
so, Length of SR = 3cm + 7cm + 3cm = 13cm
now, area of PQRS = 1/2 { length of PQ + length of SR } × length of PM
= 1/2 { 7cm + 13cm} × 4cm
= 20cm × 2 cm
= 40 cm ²
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