Question

PQRS is an isosceles trapezium in which PS = 10 cm, PQ = SR = 13 cm and the distance between PS and QR is 12 cm. Find the area of the trapezium​

Answer 1

Step-by-step explanation:

trapezium in which PS = 10 cm, PQ = SR = 13 cm and the distance between PS and QR is 12 cm. Find the area of the trapezium

Answer 2

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$\huge\sf\underline\purple{Given:-}$

• ➛Length of PS=10cm
• ➛Length of PQ=SR =13cm
• ➛between two parallel sides =12cm

$\huge\sf\underline\purple{To\: Find:-}$

• ➛Area of the Trapezium PQRS =?

$\huge\sf\underline\purple{Solve:-}$

• Let the parallel line which lies on the side SR considered be M & N

Now,

• Area of Trapezium

A = 1/2 × (Sum of parallel Sides)

• Put the value in given Formula

➛ 1/2 × ( PQ + SR)

➛ 1/2 × (13+12)

➛ 1/2 × (25)

➛ 1/2 × 25

➛ 25/2

➛12.5 sq

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