Question

???? PQRS is an isosceles trapezium. l(PQ) = 7 cm. seg PM ⊥ seg SR, l(SM) = 3 cm, Distance between two parallel sides is 4 cm, find the area of ???? PQRS

Answer 1

Length of PQ = 7 cm
Length of PM = distance between two parallel sides = 4 cm
Length of SM = 3cm
see figure, length of SR = SM + MN + NR
because PQRS is isosceles trapezium, so, SR = NR = 3cm and MN = PQ = 7cm
so, Length of SR = 3cm + 7cm + 3cm = 13cm

now, area of PQRS = 1/2 { length of PQ + length of SR } × length of PM
= 1/2 { 7cm + 13cm} × 4cm
= 20cm × 2 cm
= 40 cm ²

Answer 2

Step-by-step explanation:

3+7+3=13

now, 1/2(13+7)3

1/2×20×3

10×3

= 30 therefore the area of PQRS is 30 sq. cm