PQRS is an isosceles trapezium. PQ is parallel to SR. Sides SP and RQ are extended such that they meet at O. Prove that AP = AQ.
Answers
Answered by
3
From given information we can say that : In triangle ASR , PQ | | SR , So from converse of Basic proportionality theorem we get :
APPS = AQQR --- ( 1 )
As given : PQRS is a isosceles trapezium and we know in isosceles trapezium non parallel sides are equal to each other , So
PS = QR , Now substitute that in equation 1 and get :
APQR = AQQR⇒AP = AQQR×QR⇒AP = AQ ( Hence proved )
Hope this information will clear your doubts about topic.
If you have any more doubts just ask here on the forum and our experts will try to help you out as soon as possible.
APPS = AQQR --- ( 1 )
As given : PQRS is a isosceles trapezium and we know in isosceles trapezium non parallel sides are equal to each other , So
PS = QR , Now substitute that in equation 1 and get :
APQR = AQQR⇒AP = AQQR×QR⇒AP = AQ ( Hence proved )
Hope this information will clear your doubts about topic.
If you have any more doubts just ask here on the forum and our experts will try to help you out as soon as possible.
Similar questions