PQRS is cyclic mZPSR = 110° then find
a)
mZPQR
Р
b)
m(arc POR)
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a. Given PQRS is a cyclic quadrilateral. ∴ Opposite angles of a cyclic quadrilateral are supplementary
⇒∠PSR+∠PQR=180
⇒∠PQR=180 -110
⇒∠PQR=70
b. 2×∠PQR=m(arcPR){The measure of an inscribed angle is half the measure of the arc intercepted by it.}
m(arcPR)=140
⇒m(arcPQR)=360
−140
=220
o
{Using Measure of a major arc = 360
- measure of its corresponding minor arc}
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