Math, asked by createdonmarch4laura, 5 months ago

PQRS is rhombus with ∠QPS = 50º, Find angles a and b of figure

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Answers

Answered by pandeyyash708
0

Answer:

Step. 1 find angle PQR ( QPS and PQR are supplementary)

step 2 divide it by 2 to get angle RQS

this is because the 2 triangles SPQ and QRS are congruent

therefore Angle RQS = PQS = 1/2 PQR

the answer is -> 65°

Answered by gayatrisenapati26
0

Step-by-step explanation:

∠TRV=180

−∠UVR=180

−114

=66

(adjacent angles of a rhombus)

∠SRU=∠SRT+

2

1

∠TRV=42

+33

=75

∠QPS=∠SRU=75

(opposite angles of a parallelogram)

(ii) ∠PDQ=∠PDN−∠QDN=90

−31

=59

∠PQD=180

−∠QPS−∠PDQ=180

−75

−59

=46

(angles of a triangle)

(iii) ∠DQN=∠PDQ=59

(alternate angles of transversal)

∠MQN=180

−∠DQN=180

−59

=121

(angles on a straight line)

∴ ∠QPS=75

, ∠PQD=46

and ∠MQN=121

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