PQRS is rhombus with ∠QPS = 50º, Find angles a and b of figure
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Answer:
Step. 1 find angle PQR ( QPS and PQR are supplementary)
step 2 divide it by 2 to get angle RQS
this is because the 2 triangles SPQ and QRS are congruent
therefore Angle RQS = PQS = 1/2 PQR
the answer is -> 65°
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Step-by-step explanation:
∠TRV=180
∘
−∠UVR=180
∘
−114
∘
=66
∘
(adjacent angles of a rhombus)
∠SRU=∠SRT+
2
1
∠TRV=42
∘
+33
∘
=75
∘
∠QPS=∠SRU=75
∘
(opposite angles of a parallelogram)
(ii) ∠PDQ=∠PDN−∠QDN=90
∘
−31
∘
=59
∘
∠PQD=180
∘
−∠QPS−∠PDQ=180
∘
−75
∘
−59
∘
=46
∘
(angles of a triangle)
(iii) ∠DQN=∠PDQ=59
∘
(alternate angles of transversal)
∠MQN=180
∘
−∠DQN=180
∘
−59
∘
=121
∘
(angles on a straight line)
∴ ∠QPS=75
∘
, ∠PQD=46
∘
and ∠MQN=121
∘
[C
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