PQRS is square lawn with side PQ = 42 metres. Two circular flower
beds are there on the sides PS and QR with centre at O, the intersections of its diagonals.
Find the total area of the two flower beds (shaded parts).
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I found the figure.
Given:
2 shapes : square and circle
The circle is cut in half to form a semi-circle. The square is placed between the two semi-circle. Two semi-circles are the shaded part.
I will find the area of the shaded part which forms 1 circle.
Area of a circle = π r²
Side of the square lawn serves as the diameter of the circle. Radius is half of the diameter.
r = d/2 ⇒ 42meters ÷ 2 = 21 meters
Area of circle = 3.14 * (21m)²
A = 3.14 * 441m²
A = 1,384.74 m²
Area of the shaded parts is 1,384.74 square meters.
Given:
2 shapes : square and circle
The circle is cut in half to form a semi-circle. The square is placed between the two semi-circle. Two semi-circles are the shaded part.
I will find the area of the shaded part which forms 1 circle.
Area of a circle = π r²
Side of the square lawn serves as the diameter of the circle. Radius is half of the diameter.
r = d/2 ⇒ 42meters ÷ 2 = 21 meters
Area of circle = 3.14 * (21m)²
A = 3.14 * 441m²
A = 1,384.74 m²
Area of the shaded parts is 1,384.74 square meters.
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