PQS = 115° Q= x R= x P= y find q, r, p
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Angle PQS = 115° AND ,
Q = R = x °
Now , angle SQR = 180°
SO, PQR = 》 180° - 115° =》 65° .
SO,
angle PQR and PRQ = 》 65°
☆ Actually, The whole degree of a TRIANGLE is 180° .
Then ,
y° + x° + x° = 180°
》 y° + 2x° = 180°
》 y° + (2 × 65° ) = 180°
》 y° = 180° - 130°
》 y° = 50°
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◇ The value of "x" is -》 65°
◇ The value of "y" is -》 50°
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100% correct ⚡⚡✌✌ ______________________________
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