pqx²-(p²+q²) x+pq=0 solve this quad. Eq. by factorization method
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![x = \frac{p}{q} and \frac{q}{p} x = \frac{p}{q} and \frac{q}{p}](https://tex.z-dn.net/?f=x+%3D++%5Cfrac%7Bp%7D%7Bq%7D+and+%5Cfrac%7Bq%7D%7Bp%7D+)
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