Question

PR is the diameter of the circle with centre O. If ∠PRQ = 65, what will be the measure of ∠POQ? need explanation

Answer 1

ANSWER:

Triangle OQR is a isosceles triangle (as its two vertices i.e. Q and R touching the circumference of the circle)

So, OQ=OR

∠Q=∠R=65

∠Q+∠R+∠O=180

65+65+∠O=180

130+∠O=180

∠O=180-130

∠O=50

PR is a straight line as you know straight line always make 180 degree angle,

So, ∠O+∠O'=180      (∠O' is the angle you have to find,  just give him the

                                   other name so you don't get confused)

     50+O'=180

     ANS: O'=130    

Answer 2

Answer:

In figure, PQ is a diameter of a circle with centre O. IF ∠PQR = 650, ∠SPR = 400, ∠PQ M = 500, find ∠QPR, ∠PRS and ∠QPM.Read more on Sarthaks.com - https://www.sarthaks.com/76196/in-figure-pq-is-a-diameter-of-a-circle-with-centre-o-if-pqr-65-0-spr-40-0