Question

Pracin delhi aadhunik delhi

Answer 1

Answer:

then what is your question

Answer 2

Answer:

Case.1 : initial velocity is zero.

v = 0 + a₁t₁ = 3t₁

v = 3t₁ .......multiplying b/s by 2, we get

2v = 6t₁ ..........(i)

Case.2 : final velocity is zero.

0 = u + a₂t₂ = u + (-2)t₂

-u = -2t₂

u = 2t₂ .......multiplying b/s by 3, we get

3u = 6t₂ ..........(ii)

Adding (i) & (ii), we get

2u + 3v = 6(t₁+t₂) = 6*4 = 24

∴ maximum speed = 24 m/s

mark this answer the brainliest, if you find it so

hope it helps........

Explanation:

Case.1 : initial velocity is zero.

v = 0 + a₁t₁ = 3t₁

v = 3t₁ .......multiplying b/s by 2, we get

2v = 6t₁ ..........(i)

Case.2 : final velocity is zero.

0 = u + a₂t₂ = u + (-2)t₂

-u = -2t₂

u = 2t₂ .......multiplying b/s by 3, we get

3u = 6t₂ ..........(ii)

Adding (i) & (ii), we get

2u + 3v = 6(t₁+t₂) = 6*4 = 24

∴ maximum speed = 24 m/s

mark this answer the brainliest, if you find it so

hope it helps........Case.1 : initial velocity is zero.

v = 0 + a₁t₁ = 3t₁

v = 3t₁ .......multiplying b/s by 2, we get

2v = 6t₁ ..........(i)

Case.2 : final velocity is zero.

0 = u + a₂t₂ = u + (-2)t₂

-u = -2t₂

u = 2t₂ .......multiplying b/s by 3, we get

3u = 6t₂ ..........(ii)

Adding (i) & (ii), we get

2u + 3v = 6(t₁+t₂) = 6*4 = 24

∴ maximum speed = 24 m/s

mark this answer the brainliest, if you find it so

hope it helps........Case.1 : initial velocity is zero.

v = 0 + a₁t₁ = 3t₁

v = 3t₁ .......multiplying b/s by 2, we get

2v = 6t₁ ..........(i)

Case.2 : final velocity is zero.

0 = u + a₂t₂ = u + (-2)t₂

-u = -2t₂

u = 2t₂ .......multiplying b/s by 3, we get

3u = 6t₂ ..........(ii)

Adding (i) & (ii), we get

2u + 3v = 6(t₁+t₂) = 6*4 = 24

∴ maximum speed = 24 m/s

mark this answer the brainliest, if you find it so

hope it helps........Case.1 : initial velocity is zero.

v = 0 + a₁t₁ = 3t₁

v = 3t₁ .......multiplying b/s by 2, we get

2v = 6t₁ ..........(i)

Case.2 : final velocity is zero.

0 = u + a₂t₂ = u + (-2)t₂

-u = -2t₂

u = 2t₂ .......multiplying b/s by 3, we get

3u = 6t₂ ..........(ii)

Adding (i) & (ii), we get

2u + 3v = 6(t₁+t₂) = 6*4 = 24

∴ maximum speed = 24 m/s

mark this answer the brainliest, if you find it so

hope it helps........Case.1 : initial velocity is zero.

v = 0 + a₁t₁ = 3t₁

v = 3t₁ .......multiplying b/s by 2, we get

2v = 6t₁ ..........(i)

Case.2 : final velocity is zero.

0 = u + a₂t₂ = u + (-2)t₂

-u = -2t₂

u = 2t₂ .......multiplying b/s by 3, we get

3u = 6t₂ ..........(ii)

Adding (i) & (ii), we get

2u + 3v = 6(t₁+t₂) = 6*4 = 24

∴ maximum speed = 24 m/s

mark this answer the brainliest, if you find it so

hope it helps........