Practice Problem 10.1
A sample has 3.50 dm of solution that contains 90g of sodium chloride,
NaCl What is the molarity of that solution?
Practice Problem 10.2
on containing 18.29 HCl and 250 g of
Answers
Answered by
0
Answer:
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Explanation:
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Answered by
3
Answer:
Mass by mass % =
Massofsolution
Massofsolute
×100
=
100
.01
=0.01%
=
0.01+99.99
.01
×100
=
100
0.01
×100
Hence, mass of solute =0.01 g and mass of solvent =99.99gms.
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