Question

Practice Problems 1
1. Calculate the time period of simple pendulum of length 0.84 m when g = 9.8 ms ^-2
​

Answer 1

Answer:

9second

Explanation:

रितिक रोशन 18 22 फ्रॉगबिट

Answer 2

Answer:

The time period of a simple pendulum of length 0.84 m when $g = 9.8m/s^2$ will be $1.9385s$

​

Explanation:

The time period (T) of a simple pendulum is given by the expression,

$T = 2\pi \sqrt{\frac{l}{g} }$       ...(1)

Where g is the acceleration due to gravity and l is the length of the pendulum.

In the question, it is given that,

$l = 0.84 m$      $g = 9.8\ m/s^2$

Then substitute these values into equation(1),

$T = 2\times 3.14\times \sqrt{\frac{0.84}{9.8} }$

So we get,

The time period of the simple pendulum, $T = 1.9385 s$