Practice Problems 1
A car initially at rest, picks up a velocity of 72 kmh in 20 sec
1000 kg, find (1) Force developed by its engine (ii) Distance covered by the car
Answers
Answered by
0
Force is m*a
a=72*5/18-0/20
a=1m/s^2
F=1*1000
S=ut+1/2at^2
S=1/2*1*400
200m
a=72*5/18-0/20
a=1m/s^2
F=1*1000
S=ut+1/2at^2
S=1/2*1*400
200m
Answered by
3
Answer:
1000N-force developed by its engine
400m-distance travelled by the car
Explanation:
1)Convert 72 km/h to m/s
the answer is 20m/s
2) Therefore, acceleration=v/t
=20/20=1m/S2
3)force=mass/Acceleration
=1000/1
=1000N ( ans)
4)Distance=Speed*time
=20*20 m
=400m
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