Question

Practice Problems 1
A car initially at rest, picks up a velocity of 72 kmh in 20 sec
1000 kg, find (1) Force developed by its engine (ii) Distance covered by the car​

Answer 1

Force is m*a

a=72*5/18-0/20
a=1m/s^2

F=1*1000

S=ut+1/2at^2

S=1/2*1*400
200m

Answer 2

Answer:

1000N-force developed by its engine

400m-distance travelled by the car

Explanation:

1)Convert 72 km/h to m/s

the answer is 20m/s

2) Therefore, acceleration=v/t

=20/20=1m/S2

3)force=mass/Acceleration

=1000/1

=1000N ( ans)

4)Distance=Speed*time

=20*20 m

=400m