Practice Problems 2 :
grou 1. A cyclist and a person on a moped are acted upon by the same force. If the acceleration produced
2
by the cyclist is only th that of the moped, calculate the ratio of the masses of the cyclist
w and the moped.
5
[5:21
Answers
Answered by
0
Answer:
- 2.5:1
Explanation:
- Let acceleration of moped =a1
- Let acceleration of cyclist=a2
- from given data
- acceleration produced by cyclist
- a1=2/5a2
- forces are equal
- therefore
- m1a1=m2a2
- m1×2/5a2=m2a2
- M1/m2=5/2:1
- M1/m2=2.5:1
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Explanation:
Answer
5.0/5
2
Snehaarya
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Answer:
let the acceleration produce on mopped be a.
so, acceleration on cyclist will be (2/5)a.
now,
force on cyclist=force on mopped
or, mass of cyclist * acceleration on cyclist= mass of mopped* acceleration on mopped. ( f= ma)
or, mass of cyclist* (2/5)a= mass of mopped* a
or, mass of cyclist/ mass of mopped= a/{(2/5)a}
or, m of cylclist / m of mopped= 5a/2a
=5/2
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