Practice Problems 3 :
1. 272 calories of heat energy is required to heat 0.02 kg of a metal of specific heat capacity 170 cal kg ! °C to a
temperature T. If the initial temperature of the metal is 20°C, calculate the final temperature T. [100°C]
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Mass of metal = 0.02 kg
The temperature is T
Heat supplied to a metal =272 calories
Also,
Heat supplied = mcT
272 = 0.02 * 170 *T
T = 272
0.02*170
T = 272*10
3.4*10
T = 2720
34
T = 80
The final temperature of metal :
= 20 + 80
= 100
Hope it helped you.......
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