Question

Practice Question 1
(a) 10
1.1 If the complement of an angle is 79°, then the angle will be
in measure
(b) 11°
(c) 799
(d) 101
1.2 The difference between two complementary angles is 20°. Then, the angles are
(a) 60°, 30°
(b) 70°, 40°
(c) 20°, 50°
(d) 105°, 75°
1.3 The measure of an angle which is four times its supplement is
(a) 36°
(b) 144° (c) 16°
(d) 64°
1.4 If two supplementary angles are in the ratio 1:3, find the bigger angle.​

Answer 1

Answer:

1.1 (b)11

1.2(a)60 and 30

1.3(a)36

1.4 .135 degree

Step-by-step explanation:

1.1 let one angle be x and complement is given 75.So,x+75=90

x=90-75

x=11

1.2 . let two angles be x and y

so,x-y=30 and x+y=90

from 1st eqn,

x=30+y

put x=30+y in 2nd eqn,

x+y=90

30+y+y=90

30+2y=90

2y=90-30

y=60/2

y=30

now put y=30 in eqn

x-y=30

x-30=30

x=30+30

x=60

so ,x=60 and y=30

1.3.let two angles be x and y

x+y=180........given

x=4y

put x=4y in first eqn

so,4y+y=180

5y=180

y =180/5

y=36

hence the ans is 36

1.4.given two supplementary angles in ratio 1:3

so let the angle be 1x and 3x.

According to question,

1x+3x=180

4x=180

x=180/4

x=45

since 3x is greater than 1x,

3x=3×45

=135

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