Question

Practice Questions
1 In the figure PQ 11 Rs, and I is transversal, then what
will be the value of n?
기
P
9
2x +30
x +70°
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Answer 1

Question :

In the given figure PQ || RS, and l is Transversal, then what will be the Value of x.

To Find :

• we need to find the value of x

Given :

• PQ || RS and l is Transversal.

We know that,

As it is given in the Question that PQ is parellel to RS and l is Transversal , Then pair of Alternate angles are equal to each other.

So,

⇛∠2x + 30 = ∠x + 70

⇛ 2x - x = 70 - 30

⇛ x = 40

Hence,

• Value of x = 40

And the given angles are :-

⇛2x + 30

⇛2 × 40 + 30

⇛80 + 30

⇛110°

And,

⇛ x + 70

⇛40 + 70

⇛110°

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Answer 2

Answer:

Step-by-step explanation:

It is given that   ∠$1 = 120o$$1 = 120o$

From the figure we know that ∠1 and ∠2 form a linear pair of angles

So it can be written as

∠$1 +\leq 2 = 180o$

By substituting the values

$120o + \leq 2 = 180o$

On further calculation

$\leq 2 = 180o – 120o$

By subtraction

$\leq 2 = 60o$

From the figure we know that ∠1 and ∠3 are vertically opposite angles

So we get

$\leq 1 = \leq 3 = 120o$

From the figure we know that ∠2 and ∠4 are vertically opposite angles

So we get

∠1 = ∠5 = 120o

It is given that, l || m and t is a transversal

So the corresponding angles according to the figure is written as

$∠1 = ∠5 = 120o$

$∠2 = ∠6 = 60o$

$∠3 = ∠7 = 120o$

$∠4 = ∠8 = 60$

hope it helps

:)