Practice set 1( mathamatics)
Important for jee mains exam
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Answered by
12
Answer:
Option (a) is correct
Step-by-step explanation:
Given line ax+by+c is tangent to the curve xy=4
so we have find and equate the slope of the line and curve
Curve, xy = 4
- → x•dy/dx + y•(1) = 0
- → dy/dx = -y/x
- → dy/dx = -4/x²
slope or the line ax+by+ c = 0 is -a/b
since , the given line is tangent to the curve
- ∴ -4/x² = -a/b
- → a/b > 0
which is possible only when a>0 ,b >0 or a<0, b<0
Option (1) is marching with our posiblities so a> 0 and b>0 is answer
Answered by
2
Answer:
xy = 4
on differentiating w.r.t x , we get
(putting y = 4/x from eqn of curve)
and
ax+by+c = 0 is a tangent to the cure xy = 4. so, the slope will be -a/b.
which is possible only when a>0 and b>0 or a<0 and b<0.
Hence,(a) is correct.
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