Question

Practice set 1( mathamatics)
Important for jee mains exam ​ ​

Answer 1

$\huge \red\pi$

Answer 2

Answer:

f and g are continuous functions on [0,π]

π

let I = ∫[f(x) + g(x)]dx -----eqn(1)

0

using property of integration :-

π

I = ∫[f(π-x) + g(π-x)]dx ------eqn(2)

0

adding eqn(1) and (2):-

π

→2I = ∫[f(x)+f(π-x)+g(x)+g(π-x)]dx

0

since,f(x) + f(π-x) = g(x) + g(π-x) = 1

π

→ 2I = 2∫[f(x) + f(π-x)]dx

0

π

→ I = ∫[1]dx

0

π

→ I = [x]

0

→ I = π-0

= 0