Question

Practice Set 2.2
1. Solve the following quadratic equations by factorisation.
(3) 2y2 + 27 y + 13 = 0
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Answer 1

Step-by-step explanation:

2y^2+26y+y+13=0

2y(y+13)+1(y+13)=0

(2y+1)(y+13)=0

y=-1/2, y= -13

Answer 2

Step-by-step explanation:

2y²+27y+13=0

2y²+( 26+1 )y +13=0

2y²+26y+y+13=0

2y ( y + 13 )+1 ( y + 13 ) =0

(2y+1) (y+13)