Math, asked by rpatharwat7, 4 months ago




Practice Set 2.2
Solve the following quadratic equations by factorisation

(1) x2 - 15 x + 54 = 0

Answers

Answered by Anonymous
45

{ \bf{ \blue{ \underline{Given \:  Equation :}}}}

⇒ \: { \bf{x {}^{2} - 15x + 54 = 0}}

{ \bf{ \blue{ \underline{Solution :-}}}}

⇒ \: { \bf{x {}^{2} - 15x + 54 = 0}}

⇒ \: { \bf{x {}^{2}  - (9 - 6)x + 54 = 0}}

⇒ \: { \bf{x {}^{2}  -  9x - 6x + 54 = 0}}

⇒ \:  { \bf{x(x - 9) - 6(x - 9) = 0}}

⇒ \: { \bf{(x - 9)(x - 6) = 0}}

And now we find the value of x :-

{ \bf⇒{(x - 9 ) = 0 \: or \: (x - 6) = 0}}

⇒{ \orange{ \boxed{ \bf{x = 9 }}}}\: { \bf{or \:}} { \orange{ \boxed{ \bf{x = 6}}}}

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