Math, asked by rpbhoir, 1 month ago

Practice Set 2.6 1. Product of Pragati's age 2 years ago and 3 years hence is 84. Find her present age.
Ans :- let the present age of pragati be x years.
Pragati age 2 years ago = (x-2) years and 3 years hence =(x+3)
According to given condition,
(x-2) (x-3) =84
x²+3x-2x-6=84
x²+x-6-84=0
x²+x-90=0
x²+10x -9x-90=0
x(x+10)-9(x+10)=0
(x+10)(x-9)=0
x+10=0 or x-9=0
x=-10 or x=9
Now age cannot be negative
x=9
therefore the present age of pragati is 9 years​

Answers

Answered by aryan1726
3

Practice Set 2.6 1. Product of Pragati's age 2 years ago and 3 years hence is 84. Find her present age.

Ans :- let the present age of pragati be x years.

Pragati age 2 years ago = (x-2) years and 3 years hence =(x+3)

According to given condition,

(x-2) (x-3) =84

x²+3x-2x-6=84

x²+x-6-84=0

x²+x-90=0

x²+10x -9x-90=0

x(x+10)-9(x+10)=0

(x+10)(x-9)=0

x+10=0 or x-9=0

x=-10 or x=9

Now age cannot be negative

x=9

therefore the present age of pragati is 9 years.

Didi apne question ke saath answer post kar diya btw can you help me.

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