Question

practice set 4.2
2) construct ∆ PQR, such that QR =6.5cm, angle PQR = 60° and PQ – PR = 2.5 cm.​

Answer 1

Answer:

Steps of construction:

i. Draw seg QR of length 6.5 cm.

ii. Draw ray QT, such that ∠RQT = 600.

iii. Mark point S on ray QT such that l(QS) = 2.5 cm.

iv. Join points S and R.

v. Draw perpendicular bisector of seg SR intersecting ray QT. Name the point as P.

vi. Join the points P and R. Hence, ∆PQR is the required triangle.

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Answer 2

Answer:

Construct <RQS =60° with the help of compass. Produced XP downwards to a point X'. Set off QX'=2.5 cm; Join X'R; Draw the perpendicular .

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