Math, asked by shankardevendra903, 17 days ago

Practice Set 44 1. If the length and breadth of a rectangle are doubled, how many times the perimeter of the old rectangle will that of the new rectangle be?


=2(L+b)
=2(x+y)
=2(2x+2y)
=2x2(x+y)
=4(x+y)-2
p=2

Answers

Answered by mennx0018
0

Answer:

let length and breadth be = x and y

then perimeter = 2(x+y)

now new length and breadth = 2x and 2y

so new perimeter = 2 ( 2x+2y )

= 4(x+y)

= 2 × old perimeter

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