Question

Practice set 5.1
1. Diagonals of a parallelogram WXYZ intersect each other at point O. If ZXYZ = 135°
then what is the measure of ZXWZ and ZYZW ?
If (OY)= 5 cm then (WY)= ?
​

Answer 1

Answer:

so the answer of zxwz &zyzw are:-45 &90

Answer 2

$\Uparrow\Uparrow\Uparrow\Uparrow\Uparrow$See the Attachment.

$\huge \bigstar$$\huge\bold{\mathtt{\purple{✍︎A{\pink{N{\green{S{\blue{W{\red{E{\orange{R✍︎}}}}}}}}}}}}}$$\huge \Rightarrow$

$\Large \bold \red{Solution:}\Rightarrow$

$\angle XYZ$

$\angle XYZ=\angle XWZ$

...(Opposite angles of a parallelogram)

∴$\angle XWZ=135°$

$\angle XYZ+ \angle YZW=180°$ ...(Adjacent angles of a parallelogram are supplementry)

∴$135°+ \angle YZW=180°$

∴$\angle YZW=180°-135°$

∴$\angle YZW=45°$

$\large OY=\frac{1}{2}WY$

.... (Diagonals of a parallelogram bisect each other)

∴$\large 5=\frac {1}{2}WY$

∴$WY=5×2$

∴$WY=10cm$

∴$l(WY)=10cm$

$\Large\bold\green{Ans:}\Rightarrow$$\angle XWZ=135°,\angle YZW=45°,l(WY)=10cm$