pragya donates toys to children of an orphanage.Each toy is in the shape of a cone mounted on a hemisphere mounted on a hemisphere of common base radius 7 cm total height of the toy is 31 Cm find the total surface area of the toy
Answers
Answered by
4
According to questions,
radius of cone
r = 7 Cm
height of cone
h = 31 Cm
Also
radius of hemisphere
R = 7 Cm
Total surface area of Toy = surface area od cone + surface area of hemisphere
= pi r( r + root (h^2 + r^2) ] + 2 pi r^2
= 22/7 * 7 [ 38.78 ] + 2 * 22/7 * 49
= 1161.16 Cm^2
radius of cone
r = 7 Cm
height of cone
h = 31 Cm
Also
radius of hemisphere
R = 7 Cm
Total surface area of Toy = surface area od cone + surface area of hemisphere
= pi r( r + root (h^2 + r^2) ] + 2 pi r^2
= 22/7 * 7 [ 38.78 ] + 2 * 22/7 * 49
= 1161.16 Cm^2
Answered by
8
Solution :-
Common base radius of the toy = 7 cm
Total height of the toy = 31 cm
Height of the conical part = total height - height of the hemispherical part
31 - 7 = 24 cm
We know that,
Slant height 'l' = h² + r²
⇒ l² = 24² + 7²
⇒ l² = 576 + 49
⇒ l² = 625
⇒ l = √625
⇒ l = 25 cm
Surface area of the cone = πrl
⇒ 22/7*7*25
= 550 cm²
Surface area of hemispherical part = 2πr²
⇒ 2*22/7*7*7
= 308 cm²
Total surface area of the toy = Surface area of the conical part + Surface area of the hemispherical part
⇒ 550 + 308
= 858 cm²
Answer.
Common base radius of the toy = 7 cm
Total height of the toy = 31 cm
Height of the conical part = total height - height of the hemispherical part
31 - 7 = 24 cm
We know that,
Slant height 'l' = h² + r²
⇒ l² = 24² + 7²
⇒ l² = 576 + 49
⇒ l² = 625
⇒ l = √625
⇒ l = 25 cm
Surface area of the cone = πrl
⇒ 22/7*7*25
= 550 cm²
Surface area of hemispherical part = 2πr²
⇒ 2*22/7*7*7
= 308 cm²
Total surface area of the toy = Surface area of the conical part + Surface area of the hemispherical part
⇒ 550 + 308
= 858 cm²
Answer.
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