Question

pragya donates toys to children of an orphanage on the occasion of her birthday. each toy is in the shape of a cone mounted on a hemisphere of common base radius 7cm. the total height of the toy is 31cm. find total surface area of toy. also find the cost of 50 such toys if cost of material used for coloring the toys is RS. 5 per 100cm^2 and cost of manufacturing is RS. 10 per toy.

Answer 1

Please tell me its final answer if you have

Answer 2

Answer:

Radius of hemisphere and cone = 7 cm

Height of toy = 31 cm

Height of cone = 31 cm - 7 cm = 24 cm

Curved surface area of cone = $\pi r (\sqrt{h^2+r^2})$

Curved surface area of cone = $\frac{22}{7} \times 7 (\sqrt{24^2+7^2})$

Curved surface area of cone = $550 cm^2$

Curved surface area of hemisphere = $2 \pi r^2 = 2 \times \frac{22}{7} \times 7^2 = 308 cm^2$

Total surface area of toy = 550+308 = 858 sq.cm.

Surface area of 50 toys = 858*50 =42900 sq.cm.

Cost of material used for coloring the toys is RS. 5 per 100 sq.cm.

Cost for 1 sq.cm= $\frac{5}{100}$

Cost for 42900 sq.cm= $\frac{5}{100} \times 42900=2145$

So, the cost of 50 such toys if cost of material used for coloring the toys is RS. 5 per 100 sq.cm. is Rs.2145

Cost of manufacturing is RS. 10 per toy.

Cost of manufacturing of 50 toys = 50* 10 =500

Hence the cost of 50 such toys if cost of material used for coloring the toys is RS. 5 per 100 sq.cm. is Rs.2145  and Cost of manufacturing of 50 toys is Rs. 500