Chemistry, asked by mujeebkaryakath, 8 months ago

Pragya tested the Solubility of three different
temperature and collected the data as given below
results given in the following table, as grams of substance dissolved in 100 grams of water to forma a
Swturated Solution.)​

Answers

Answered by apranideep37
10

Answer:

(a) Mass of potassium nitrate present in 100g of water in a saturated

solution at 313 K = 62g

∴ Mass of potassium nitrate in 50 g of water in the saturated solution

at 313 K = × = 62

100

50 31 g

g

g g.

(b) When a saturated solution of potassium chloride at 353 K is cooled,

the solubility of potassium chloride in water decreases. As a result,

the amount of potassium chloride which exceeds its solubility at

lower temperature separates out as crystals.

(c) Solubility of potassium nitrate at 293 K = 32 g/100 g H2

O

Solubility of sodium chloride at 293 K = 36 g/100 g H2

O

Solubility of potassium chloride at 293 K = 35 g/100 g H2

O

Solubility of ammonium chloride at 293 K = 37 g/100 g H2

O

From the above data, it is evident that ammonium chloride has the

highest solubility at 293 K.

(d) In general, the solubility of a salt increases with temperature. The

increase is, however, different for different salts. For example,

the solubility of potassium nitrate increases appreciably, that of

ammonium chloride increase slightly, that of potassium chloride

Explanation:

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