Prakash accelerates uniformly from 18 km per hour 36 km per hour in 5 seconds calculate the acceleration
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Given that,
u= 18km/hr = 18X5/18= 5m/s
v=36km/hr = 36X5/18= 10m/s
t=5sec
Acc.= v-u/t
a= 10-5/5
Hence, a= 1m/s²
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