Question

Pramod can do 2/7 th of the work in 8 days and Binod can finish the remainder in 20 days. How long would they take to finish it together?​

Answer 1

Answer:

don't know the answer

Step-by-step explanation:

sorry

Answer 2

Given:

Time taken by Pramod to do 2/7 of the work = 8 days

Time taken by Binod to do remaining (i.e., 5/7 of the work) = 20 days.

Solution:

Pramod completes 2/7 work in 8 days

Time taken by Pramod to complete the whole work = $\frac{8}{(2/7)}$ = 8 x 7/2 = 28 days.

Binod completes the remaining work i.e., 5/7 work in 20 days.

Time taken by Binod to complete the whole work = $\frac{20}{(5/7)}$ = 20 x 7/5 = 28 days.

Total work = L.C.M. of 28 and 28 = 28 units

Combined efficiency of Pramod and Binod = 28/28 + 28/28

                                                                       = 1 + 1  = 2 units / day

Time taken by Pramod and Binod to finish the whole work together = 28/2

                                                                     = 14 days

Hence, they would take 14 days to finish it together.

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