Pranali and prasad started walking to east and to north respectively,from the same point and at same speed.After 2 hours distance between them was 15√2km.Find their speed per hours.
Answers
distance=15√2/√2=15
speed=d/T
=15/2
=7.5km/hr
hey mate
here is your answer
Now, Refers the attachment for the Question.
Distance between Pranali and Prasad after 2 hours = 15/√2 km.
= 15/√2 × √2/√2
= (15√2)/2
= 7.5√2 km.
Let the Speed of the Pranali and the Prasad be x km/hr.
[Since there speed is same.]
Now, For Pranali,
Time = 2hrs.
Distance = BC.
∵ Speed = Distance/Time
∴ Distance(BC) = Speed × Time.
∴ BC = x × 2
⇒ BC = 2x
For Prasad,
Time = 2 hrs.
Distance = AB
∴ Distance(AB) = x × 2
= 2x
We can see that Distance covered by both of them is similar,
Now, From the attachment,
Applying Pythagoras Theorem,
AC² = AB² + BC²
⇒ (7.5√2)² = (2x)² + (2x)²
⇒ 112.5 = 4x² + 4x²
⇒ 8x² = 112.5
⇒ x² = 112.5/8
⇒ x² = 14.0625
⇒ x = √14.0625
⇒ x = 3.75
∴ Distance covered by Pranali and Prasad is 3.75 km.
Now, For the Speed,
∵ Speed = Distance/Time
∴ x = 3.75/2
∴ x = 1.875 km/hr.
Hence, Speed of the Pranali and the Prasad is 1.875 km/hr.
Hope it helps.
✔️✔️✔️