Math, asked by sharankn6445kvk, 18 hours ago

Pranav’s age is 15 years more than three timesthe Raju’s age. Find the Raju’s age if the
Pranav’s age is 45 years.

Answers

Answered by vnmvs1205
1

Answer:

x = 10

Step-by-step explanation:

Let Raju’s age will be x

3x + 15 = 45

3x = 30

x = 10

Answered by RvChaudharY50
1

Given :- Pranav’s age is 15 years more than three times the Raju’s age. Pranav’s age is 45 years.

To Find :- Raju’s age = ?

Solution :-

Let us assume that, Raju’s age is equal to x years .

So,

→ Pranav’s age = 15 years more than three times the Raju’s age .

→ Pranav’s age = 3 × Raju’s age + 15

→ Pranav’s age = 3 × x + 15

→ Pranav’s age = 3x + 15

given that, Pranav’s age is 45 years .

then,

→ 45 = 3x + 15

→ 45 - 15 = 3x

→ 30 = 3x

→ 3 × 10 = 3 × x

dividing both sides by 3,

→ x = 10 years (Ans.)

Verification :-

→ Pranav’s age = 3 × Raju’s age + 15

→ 45 = 3 × 10 + 15

→ 45 = 30 + 15

→ 45 = 45

→ LHS = RHS

Hence, Raju’s age is equal to 10 years .

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