pranay 's father is seven times his age now.Two years later he will be five times as old as his son will be.Find their present age.
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Answered by
38
let pranay's age be x
his father's age =7x
two years later
5(x+2)=7x+2
5x+10=7x+2
8=2x
x=4
pranay's age is 4years
and his fathers =4×7=28years
his father's age =7x
two years later
5(x+2)=7x+2
5x+10=7x+2
8=2x
x=4
pranay's age is 4years
and his fathers =4×7=28years
ansss:
hope it helps
Answered by
19
let pranay's present age be x
then his father ' s age 7x
after 2 yrs pranay' s father age (7x+2)
pranay' s age (x+2)
according to given question
(7x+2)=5(x+2)
7x+2=5x+10
7x-5x=10-2
2x=8
x=4
therefore pranay's age = 4yrs
his father's age = 28
then his father ' s age 7x
after 2 yrs pranay' s father age (7x+2)
pranay' s age (x+2)
according to given question
(7x+2)=5(x+2)
7x+2=5x+10
7x-5x=10-2
2x=8
x=4
therefore pranay's age = 4yrs
his father's age = 28
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