Math, asked by Reg6alShrgri, 1 year ago

pranay 's father is seven times his age now.Two years later he will be five times as old as his son will be.Find their present age.

Answers

Answered by ansss
38
let pranay's age be x
his father's age =7x
two years later
5(x+2)=7x+2
5x+10=7x+2
8=2x
x=4
pranay's age is 4years
and his fathers =4×7=28years 


ansss: hope it helps
Answered by arun8
19
let pranay's present age be x
then his father ' s age 7x

after 2 yrs pranay' s father age (7x+2)
pranay' s age (x+2)

according to given question

(7x+2)=5(x+2)

7x+2=5x+10

7x-5x=10-2

2x=8
x=4
therefore pranay's age = 4yrs
his father's age = 28

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