Math, asked by sreeshamalhoglitma, 1 year ago

pranay's father is seven times his age now.Two years later he will be five times as old as his son will be.Find their present age.

Answers

Answered by mysticd
3
let at present
Pranay 's age = x years
father age = 7x years
two years later
Pranay's age = x+2
father age = (7x+2) years
father age = 5* son age
7x+2 = 5(x+2)
7x+2 = 5x+10
7x-5x = 10-2
2x = 8
x= 8/2 =4
x= 4
at present
Pranay age = x = 4 years
father age = 7x = 7*4= 28 years
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