pranay's father is seven times his age now.Two years later he will be five times as old as his son will be.Find their present age.
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let at present
Pranay 's age = x years
father age = 7x years
two years later
Pranay's age = x+2
father age = (7x+2) years
father age = 5* son age
7x+2 = 5(x+2)
7x+2 = 5x+10
7x-5x = 10-2
2x = 8
x= 8/2 =4
x= 4
at present
Pranay age = x = 4 years
father age = 7x = 7*4= 28 years
Pranay 's age = x years
father age = 7x years
two years later
Pranay's age = x+2
father age = (7x+2) years
father age = 5* son age
7x+2 = 5(x+2)
7x+2 = 5x+10
7x-5x = 10-2
2x = 8
x= 8/2 =4
x= 4
at present
Pranay age = x = 4 years
father age = 7x = 7*4= 28 years
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