Math, asked by khanejasaksham54, 6 months ago

Pranay wants to stack few one-rupee coins and some five-rupee coins in such a way that:

a. Each stack has the same number of coins.

b. There is least number of stacks.

c. Each stack either has one rupee or five-rupee coins.

d. No coins are left over after creating stacks.

His first step to find the number of coins that should be in each stack is 195=1(180) +15. Given that he

has more of five-rupee coins than one-rupee coins, how many one-rupee coins stack can he make?​

Answers

Answered by amitnrw
6

Given : first step to find the number of coins that should be in each stack is 195=1(180) +15

he  has more of five-rupee coins than one-rupee coins,

To Find  :  how many one-rupee coins stack can he make

Solution:

195=1(180) +15

This is the Method to find HCF

As rs 5 coins are more

Hence

Rs 5 coins = 195

& Rs 1 coins = 180

HCF

195=1(180) +15

180 = 12(15)

15 is the HCF

Rs 1 coins = 180    Hence  He can make  one-rupee coins stack  = 12

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Answered by yusengar
0

Answer:

12 is the answer this is the correct answer but 15 is the hcf

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