Pranay wants to stack few one-rupee coins and some five-rupee coins in such a way that:
a. Each stack has the same number of coins.
b. There is least number of stacks.
c. Each stack either has one rupee or five-rupee coins.
d. No coins are left over after creating stacks.
His first step to find the number of coins that should be in each stack is 195=1(180) +15. Given that he
has more of five-rupee coins than one-rupee coins, how many one-rupee coins stack can he make?
Answers
Answered by
6
Given : first step to find the number of coins that should be in each stack is 195=1(180) +15
he has more of five-rupee coins than one-rupee coins,
To Find : how many one-rupee coins stack can he make
Solution:
195=1(180) +15
This is the Method to find HCF
As rs 5 coins are more
Hence
Rs 5 coins = 195
& Rs 1 coins = 180
HCF
195=1(180) +15
180 = 12(15)
15 is the HCF
Rs 1 coins = 180 Hence He can make one-rupee coins stack = 12
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Answered by
0
Answer:
12 is the answer this is the correct answer but 15 is the hcf
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