prasad saves 1 on July 1st 3 on July 2nd, 5 on July 3rd and continues saving in this process. Then find his total savings in the month of July.
Answers
Answered by
0
Answer:
Surendra's savings are Rs. 1, Rs. 2, Rs. 3,.... which is an A.P.
Here, t
1
=1, n=20
t
n
=t
20
=20; S
n
=S
20
=?
Therefore, S
n
=
2
n
(t
1
+t
n
)
⇒S
20
=
2
20
(1+20)
⇒S
20
=
2
20
×21=210
Hence, Surendra's total savings after 20 days will be Rs. 210.
Answered by
1
Answer:
Surendra's savings are Rs. 1, Rs. 2, Rs. 3,.... which is an A.P.
Here, t
1
=1, n=20
t
n
=t
20
=20; S
n
=S
20
=?
Therefore, S
n
=
2
n
(t
1
+t
n
)
⇒S
20
=
2
20
(1+20)
⇒S
20
=
2
20
×21=210
Hence, Surendra's total savings after 20 days will be Rs. 210.
Step-by-step explanation:
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