Math, asked by swathipolluru307, 12 hours ago

prasad saves 1 on July 1st 3 on July 2nd, 5 on July 3rd and continues saving in this process. Then find his total savings in the month of July.​

Answers

Answered by shakshi015724
0

Answer:

Surendra's savings are Rs. 1, Rs. 2, Rs. 3,.... which is an A.P.

Here, t

1

=1, n=20

t

n

=t

20

=20; S

n

=S

20

=?

Therefore, S

n

=

2

n

(t

1

+t

n

)

⇒S

20

=

2

20

(1+20)

⇒S

20

=

2

20

×21=210

Hence, Surendra's total savings after 20 days will be Rs. 210.

Answered by RKRUHIRK
1

Answer:

Surendra's savings are Rs. 1, Rs. 2, Rs. 3,.... which is an A.P.

Here, t

1

=1, n=20

t

n

=t

20

=20; S

n

=S

20

=?

Therefore, S

n

=

2

n

(t

1

+t

n

)

⇒S

20

=

2

20

(1+20)

⇒S

20

=

2

20

×21=210

Hence, Surendra's total savings after 20 days will be Rs. 210.

Step-by-step explanation:

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