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Answer:
The zeroes of the quadratic polynomial x2 + 99x + 127 are
(a) Both positive
(b) Both negative
(c) One positive and one negative
(d) Both equal
Step-by-step explanation:
(b) Let given quadratic polynomial be p(x) =x2 + 99x + 127.
On comparing p(x) with ax2 + bx + c, we get
a = 1, b = 99 and c = 127
Hence, both zeroes of the given quadratic polynomial p(x) are negative.
Alternate Method
the above condition.
So, both zeroes of the given quadratic polynomial are negative.
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