Question

prashant claims that the polynomial p(x)=mx^2+x^2b(a>2b)has 4b zero for Prashant . chose the correct options 1. a=2b, a=4b 2.a=2b , a=2​

Answer 1

SOLUTION

CORRECT QUESTION

TO CHOOSE THE CORRECT OPTION

prashant claims that the polynomial

$\sf p(x) = m {x}^{a} + {x}^{2b} \: \: (a > 2b)$

has 4b zeroes. For Prashant claim to be correct which of these must be true

(a) a = 2 or a = 4b

(b) a = 4b

(c) m = 2b

(d) m = 4b

EVALUATION

Here the given polynomial is

$\sf p(x) = m {x}^{a} + {x}^{2b}$

Now it is stated that a > 2b

The variable is x

Since it is given that the polynomial has 4b zeroes

So degree of the polynomial = 4b

Thus the highest power of its variable that appears with nonzero coefficient is 4b

Then we have a = 4b

FINAL ANSWER

Hence the correct option is (b) a = 4b

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Answer 2

Options

(a) a=2 or a=4b

(b) a=4b

(c) m=2b

(d) m=4b

Here the given polynomial

p(x) = mx^a+x^2b (a>2b) where (a>2b)

Now it is stated that a > 2b

The variable is x

Since it is given that the polynomial has 4b zeroes

So degree of the polynomial = 4b

Thus the highest power of its variable that appears with nonzero coefficient is 4b

Then we have a = 4b