Question

prateek purchased 50 kg of apples for rupiya 1200 and sold them at the rate of rupiya 21per kg . find his loss or gain percent

Answer 1

Answer:

x² - 16x - 1200 = 0

Step-by-step explanation:

1200/x

If 10 rot the new number is x - 10

The selling price for the remaining apples is 1200 + 60 = 1260

1260/(x - 10) is the selling price of each apple.  

This is equivalent to the cost price plus 10 which is as shown :

1200/x + 10

To solve for x, we equate the two.  

That is :

1200/x + 10 = 1260 / (x - 10)

1200 (x - 10) + 10x (x - 10) = 1260x

1200x - 12000 + 10x² - 100x = 1260x

1260x - 1200x + 100x - 10x² + 12000 = 0

10x² - 160x - 12000 = 0

Dividing through by 10 we have :

x² - 16x - 1200 = 0

From this we solve for x using quadratic formula.  

The equation is thus :

x² - 16x - 1200 = 0

Answer 2

Prateek purchased =50kg for 1200 rs

1 kg cost=1200/50=24 rs.

sold at= 21 per kg.

loss%= loss*100/cp

24-21=3

loss%= 3*100/21

loss%=14.28%