Question

Prave that 6+√2 is irrational
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Answer 1

Answer:

Step-by-step explanation:

Let us assume 6+√2 to be rational

Then,

6+√2 = a/b [where a and b are co-prime integers, and b not equals 0]

√2 = a/b - 6

√2 = (a-6b)/b

This, shows that √2 is also rational

But it contradicts the fact that √2 is irrational.

This contradiction arises due to our incorrect assumption (that 6+√2 is rational)

Therefore, 6+√2 is irrational

HENCE PROVED

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