Praveen has rupees 4662 in the from of 2 and 5, 10 rupees notes. if these notes are in the ratio of 3:5:8 the number of five rupees notes within him is
Answers
Answered by
32
Answer:
- Number of 2 rupees notes =126
- Number of 5 ruppes notes =210
- Number of 10 rupees notes = 336
Given :
- Praveen has rupees 4662 in the from of 2 and 5, 10 rupees notes.
- These notes are in the ratio of 3:5:8.
To find :
- The number of five rupees notes within him =?
Step-by-step explanation:
Let number of 2 rupees notes =3x
Then, number of 5 rupees notes=5x
And, number of 10 rupees notes =8x
According to the question :
2(3x)+5(5x)+10(8x)=4662
6x+25x+80x=4662
111x=4662
x = 4662/111
x = 42
Hence,
- Number of 2 rupees notes, 3x = 3×42=126
- Number of 5 ruppes notes, 5x =5×42=210
- Number of 10 rupees notes,8x= 8×42=336
Answered by
162
Given :
Total rupees praveen has = Rs. 4662
In which there were 2 , 5 and 10 Rupees notes.
Assuming the notes are in ratio of 3:5:8
To find :
Total no. of Rs. 5 notes
Solution:
Let x to be included in the ratio then 3x , 5x and 8x
Let the no. of Rs 2 , Rs 5 and Rs 10 be 3x , 5x and 8x
Now According to question,
3x × 2 + 5x × 5 + 10x × 8 = Rs. 4662
= 6x + 25x + 80x = Rs.4662
= 111x = Rs. 4662
=> x = Rs. 4662/111
x = Rs. 42
Now finding the no. of all Rs. 2 , Rs. 5 and Rs.10 notes
No. of Rs.2 notes = 3× 42 = 126
No. of Rs.5 notes = 5 × 42 = 210
No. of Rs.10 notes = 8 × 42= 336
In question, it is asking the no. of only Rs. 5 notes
= 210
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