Question

Praveen has rupees 4662 in the from of 2 and 5, 10 rupees notes. if these notes are in the ratio of 3:5:8 the number of five rupees notes within him is​

Answer 1

Given :

• Total rupees praveen has = Rs. 4662

• In which there were 2 , 5 and 10 Rupees notes.

Assuming the notes are in ratio of 3:5:8

To find :

• Total no. of Rs. 5 notes

Solution:

Let x to be included in the ratio then 3x , 5x and 8x

Let the no. of Rs 2 , Rs 5 and Rs 10 be 3x , 5x and 8x

Now According to question,

3x × 2 + 5x × 5 + 10x × 8 = Rs. 4662

= 6x + 25x + 80x = Rs.4662

= 111x = Rs. 4662

=> x = Rs. 4662/111

x = Rs. 42

Now finding the no. of all Rs. 2 , Rs. 5 and Rs.10 notes

No. of Rs.2 notes = 3× 42 = 126

No. of Rs.5 notes = 5 × 42 = 210

No. of Rs.10 notes = 8 × 42= 336

In question, it is asking the no. of only Rs. 5 notes

= 210 .

Answer 2

Answer:

Let number of 2 rupees notes =3n

Then, number of 5 rupees notes=5n

And, number of 10 rupees notes =8n

According to the question :

2(3n)+5(5n)+10(8n)=4662

6n+25n+80n=4662

111n=4662

n = 4662/111

n = 42

Hence,

Number of 2 rupees notes, 3n = 3×42=126

Number of 5 ruppes notes, 5n =5×42=210

Number of 10 rupees notes,8n= 8×42=336